[ARC5] Audio power output - 10 meter BC-454

[Kenneth G. Gordon]

On 16 Feb 2013 at 15:32, Ian Wilson wrote:

> 
> Hi Ken,
> 
> P = (Vrms * Vrms)/R

Ah! E(rms)^2/R, NOT E(pk-pk)^2/R then.

But sqrt2 = 1.414~

So we have then:

(35/1.414)^2/500=1.22 watts then.

Still darned loud here.

Thanks, Ian.

Ken W7EKB