[TheForge] allstate oxy-propane torch

[terry l. ridder]

hello;

On Tue, 17 Aug 2004, Rich Maynard wrote:

rich> Some observations;
rich> 
rich> Your table talks about molecules of gas combining in a chemical reaction.
rich> 

actually it could just as well be cubic feet, cubic meters, kmol, mol,
etc. the ratios are still the same.

rich> 
rich> You take no account of the volumes of gas this represents (which is probably
rich> closest to what we would measure in practice).
rich> 

see above.

rich> 
rich> You take no account of the fact that burning one molecule of methane will
rich> produce less heat than burning one molecule of gasoline (for example).
rich> 

no i did not. the posting address oxygen consumption only.
i did not address the inner and outer flame characteristics of the fuel
gases.

rich> 
rich> Also, the heat needed for the cutting of steel comes about largely from the
rich> reaction between oxygen and the iron in the steel, and not from burning the
rich> fuel.
rich> 

agreed. in cutting the 99% pure oxygen is doing the cutting. the
oxy-fuel is used only for pre-heating.

rich> 
rich> Cheers,
rich> 
rich> Rich.
rich> 

terrylr>
terrylr> methane   == CH4
terrylr> acetylene == C2H2
terrylr> ethylene  == C2H4
terrylr> ethane    == C2H6
terrylr> propylene == C3H6
terrylr> propane   == C3H8
terrylr> butylene  == C4H8
terrylr> butane    == C4H10
terrylr> gasoline  == C8H18
terrylr> hydrogen  == H2
terrylr> oxygen    == O2
terrylr>
terrylr>           fuel        oxygen         carbon      water
terrylr>           gas                        dioxide     vapor
terrylr> methane   CH4(g)   + ( 2.0)O2(g) = (1)CO2(g) + (2)H20(g)
terrylr> acetylene C2H2(g)  + ( 2.5)O2(g) = (2)C02(g) + (1)H20(g)
terrylr> ethylene  C2H4(g)  + ( 3.0)O2(g) = (2)CO2(g) + (2)H20(g)
terrylr> ethane    C2H6(g)  + ( 3.5)O2(g) = (2)CO2(g) + (3)H20(g)
terrylr> propylene C3H6(g)  + ( 4.5)O2(g) = (3)CO2(g) + (3)H20(g)
terrylr> propane   C3H8(g)  + ( 5.0)O2(g) = (3)CO2(g) + (4)H20(g)
terrylr> butylene  C4H8(g)  + ( 6.0)O2(g) = (4)CO2(g) + (4)H20(g)
terrylr> butane    C4H10(g) + ( 6.5)O2(g) = (4)CO2(g) + (5)H20(g)
terrylr> gasoline  C8H18(g) + (12.5)O2(g) = (8)CO2(g) + (9)H20(g)
terrylr> hydrogen  H2(g)    + ( 0.5)O2(g) =             (1)H2O(g)
terrylr>
terrylr>           oxygen to fuel gas ratios
terrylr>

-- 
terry l. ridder ><>