[R-390] Ballastubes (was inrush current limiters)
Bill Smith
[email protected]
Tue, 24 Dec 2002 13:55:22 -0800
Haven't tried it yet, but seems simple enough:
Why not made a 300ma current source (zenner, two resistors, transistor, or
your improvement) and hook it up to the +/- terminals of a bridge rectifier.
Hook the AC terminals of the bridge rectifier to pins 2 and 7 of the
ballast.
The current source always sees DC, and the circuit works in the AC line of
the filament string.
Merry Christmas and Happy Holidays!
73 de Bill, AB6MT
[email protected]
----- Original Message -----
From: "Jim Shorney" <[email protected]>
To: "Cecil Acuff" <[email protected]>; <[email protected]>
Sent: Tuesday, December 24, 2002 1:06 PM
Subject: Re: [R-390] Ballastubes (was inrush current limiters)
> -----BEGIN PGP SIGNED MESSAGE-----
>
> On Mon, 23 Dec 2002 21:58:34 -0600, Cecil Acuff wrote:
>
> >You arrived at peak value by half wave rectifying the Peak to Peak sine
> >wave. You now multiply that value by .707 to get the RMS value. To go
from
> >RMS back to Peak you multiply by 1.414 and then double that to get Peak
to
> >Peak values.
>
> That doesn't apply to the output of a half-wave rectifier. It only
> applies to a pure sinewave or full-wave rectified sine wave (allowing
> for diode voltage drop if you're dealing with low voltages). As Drew
> pointed out, the RMS value of a half-wave rectified sine wave is
> .5*peak.
>
> - --
> Jim Shorney -->.<--Put complaints in this box
> [email protected]
> [email protected]
> Ham Radio NU0C
> Lincoln, NE, USA
> EN10PT
> http://incolor.inetnebr.com/jshorney/
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