[Lowfer] Epson Question

Tue, 20 Apr 2004 03:00:44 -0400

Dick

>So... if the oscillator is putting out a square wave, but your antenna
>filters out the harmonics, then you need to multiply by yet another number.
>Its something like 65% - anyone have one that's been carefully worked out?

Simply treat the square wave as a sine wave with equal amplitude and use P = 
V^2/8*R.  BTW, the 8 in the denominator comes from 1/(sq rt 2)^2 , the 
conversion of p-p to RMS for a sine wave.

Bill

>on 4/18/04 12:49 PM, Bill Ashlock at [email protected] wrote:
>
> >> What is the power output of an the Epson oscillators we use for HiFER 
>in mW
> >> or dB?  I don't see specs on this in any of my catalogs.
> >
> > Kurt the output power depends on the voltage out and the load 
>resistance.The
> > basic formula for power in a load of course is P= V^2/R  where V = RMS
> > voltage applied to a resistive load R. The tricky part is converting the
> > waveform to RMS.  For a sine wave the above formula becomes P = V^2/8*R
> > where V is measured peak to peak. For a square wave it's P= V^2/4*R 
>where V
> > is also in peak to peak volts.
> >
> > Bill
> >
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