[Laser] 5mw laser transceiver kit

[Mike]

  > ... Here's a group of 48 IR LED's ... Any mfr claim from China is 
AUTOMATICALLY suspicious. Ya gotta' measure them yourself.

How _do_ you measure the optical power from 48 NIR LEDs?


Tom

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Tom & et al,

Good question, that's why I mentioned the Tek J-16 with the J6502 Irradiance
probe. How do you attenuate the front end in order to accommodate the higher
power signal?

The Sun: Since we have a KNOWN source, the sun, how do we use it as a
reference? The sun puts out 1366W / square meter, right? So does that mean
the 'power' hitting (from the sun) on a 1 square cm of detector has 1/10000
of the 1366W to yield .1366W? 

Back to the J-16 and the J6502 detector. The max attenuation is 1000 on the
1.9uW / CM squared scale. Here's a picture:
http://www.mgte.com/tek_j-16.jpg
What would be the amount and number of the (photographic) ND filter to use?
And NO selecting x 1000 on the J-16 is NOT enough. (I actually used 4
Polaroid filters, in series, twisted enough to bring it within range of the
J-16 BUT the results were inconclusive because I did NOT know how much I was
actually attenuating the sun by. Anybody care to help me out there?)

Another idea is:
'Wall-wart' power. Well maybe not but how about current and voltage
measurements "through" the laser in question? If not then what is the
conversion between "measured" and "radiated" power? (steradians... per.....
cm2)? I am rather isolated or I'd be 'tapping' my gurus who do know. :)

Your shot.

Mike C.