[ICOM] Icom 706MKII and current draw
Dick Dievendorff
dieven at comcast.net
Mon Jun 16 15:42:57 EDT 2008
Actually, I believe that Ohm's law is the relationship between current,
voltage and resistance.
The power formula, P = EI, isn't Ohm's Law. I'm not sure whose law it is,
though!
Dick, K6KR
-----Original Message-----
From: icom-bounces at mailman.qth.net [mailto:icom-bounces at mailman.qth.net] On
Behalf Of STeve Andre'
Sent: Monday, June 16, 2008 12:15 PM
To: icom at mailman.qth.net
Cc: IcomIC706mk2g at yahoogroups.com; ic706 at yahoogroups.com
Subject: Re: [ICOM] Icom 706MKII and current draw
On Monday 16 June 2008 15:00:16 Howard W3CQH wrote:
> ----- Original Message -----
> From: "John Geiger" <aa5jg at lcisp.com>
> To: "ICOM Reflector" <icom at mailman.qth.net>; <ic706 at yahoogroups.com>;
> <IcomIC706mk2g at yahoogroups.com>
> Sent: Monday, June 16, 2008 2:37 PM
> Subject: [ICOM] Icom 706MKII and current draw
>
> > Does anyone know how much current the 706MKII draws when running full
> > power
> > on 2 meters (20 watts).
> >
> > 73s John AA5JG
> > (ex: W5TD, NE0P)
> > 6M WAS #1275, 6m VUCC #1260
> > 2m VUCC #615, Satellite VUCC #129
>
> How about ohms law: E x I = P or I = P/E - therefore 20 watts divided by
> 13.2 should draw 1.5a...
Except that radios aren't 100% efficient. If its 50%, then more like 3A,
and
I'd not be surprised if it was 4A.
--STeve Andre'
wb8wsf en82
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