[Ham-Computers] Need information.

[Loren Moline WA7SKT]

Im sorry..I think I messed up..will re-calculate

 
Loren   WA7SKT
 
Member: ARRL and Pacific Northwest VHF Society
Member: Hearsat Satellite Monitoring Group ( www.hearsat.org )
Location: CN86bx                                                                                        
                          
                                 







> From: lmoline at hotmail.com
> To: ham-computers at mailman.qth.net
> Date: Mon, 26 Dec 2011 11:33:43 -0800
> Subject: Re: [Ham-Computers] Need information.
> 
> 
> Ken,
> 
> 35% would be 1 part concentrate to 2.86 parts water and 3.5% would be 1 part concentrate to 28.6 parts water so if you mix the solution as follows.
> 
> 1 part concentrate to 28.6 parts water minus 1 part concentrate to 2.86 parts water equals 25.75 parts water.
> 
> So if I am right if you mix 1 part of 35% solution to 25.75 parts water you will have a 3.5% solution.
> 
>  
> Loren   WA7SKT
>  
> Member: ARRL and Pacific Northwest VHF Society
> Member: Hearsat Satellite Monitoring Group ( www.hearsat.org )
> Location: CN86bx                                                                                        
>                           
>                                  
> 
> 
> 
> 
> 
> 
> 
> > From: n5cm at rtconline.com
> > To: boatanchors at mailman.qth.net; boatanchors at theporch.com; ham-computers at mailman.qth.net
> > Date: Mon, 26 Dec 2011 07:42:39 -0600
> > Subject: [Ham-Computers] Need information.
> > 
> > Hi Folks,
> > Please excuse but I desperately need information. My math ain't what it used to be!
> > 
> > Can someone tell me how to mix 35% solution with clean water to get a 3% solution. 
> > I bought a quantity of "food grade 35% solution  h2o2 and need the 3% solution. 
> > While at it, how about a 35% solution down to an 8% solution for agricultral purposes?
> > My heartfelt thanks. My math never was anything to brag about and far worse now tho I am only 94 years of age!
> > 
> > Ken  N5CM
> > 
> > 
> > 
> > 
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