[Ham-Computers] Re: Ham-Computers Digest, Vol 43, Issue 15
va3hsc at hotmail.com
va3hsc at hotmail.com
Mon Aug 27 11:49:28 EDT 2007
E E= volts
------- -------------------------
I R I=amps R=resistance
P P=power/watts
-------- -------------------
E I E=volts I=amps
E x I = P
13.8 x 8 = 110.4
P / E = I
110.4 / 13.8 = 8
P / I = E
110.4 / 8 = 13.8
110.4 watts an hour
60 minutes in an hour divided by your 20 minutes
60 / 20 = 3
110.4 / 3 = 36.8 watts
You need 36.8 watts of power for 20 minutes
10 percent loss of power storing into batteries
6 percent loss of power in wires, controller, ETC.
36.8 + 16 percent = 42.688 watts of solar on a sunny day with the
sun a 90 degrees to the panel for one hour.
My self I would times it by three 42.688 x 3 = 128.064 watt solar
panel.
> Message-ID: <001701c7e86b$df3e5f60$8666f504 at ELNkk7rc>
> Content-Type: text/plain; charset="iso-8859-1"
>
> Why should it be so hard for me to find a webpage that will tell me how
> large a solar panel I need to run a system drawing 8 Amperes at 13.8 VDC
> for
> 15 to 20 minutes per day???
>
> Any suggestions?
>
> Thanks,
>
> Kurt
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