[Elecraft] [K2] DC Input (was:N2CQ QRP Contest Calendar: Nov 2007)

[Paul Fletcher]

Would this method work?

Put the K2 into test mode (see manual page 100) and measure the key down TX
input power (disables PA).

Your maximum allowed input power is 10W plus the figure measured.

Regards,
Paul M1PAF.

-----Original Message-----
From: elecraft-bounces at mailman.qth.net
[mailto:elecraft-bounces at mailman.qth.net] On Behalf Of David Woolley
Sent: 31 October 2007 22:37
To: List Elecraft
Subject: [Elecraft] [K2] DC Input (was:N2CQ QRP Contest Calendar: Nov 2007)

Ken Newman wrote:
> HA-QRP Contest (CW - 80 Meters) *** QRP Contest***
> Nov 1, 0000z to Nov 7, 2400z
> Rules: http://www.radiovilag.hu/haqrp2.htm

The rules for this specify a limit of 10 watts DC input.  Is there
any sensible way of calculating a, non-zero,  absolute lower bound for 
the power consumed by the K2 driver and exciter, so as to be able to
honestly say that the PA DC input is less than 10 watts without
limiting the total current to 750 to 800 mA to make the whole
transceiver transmit mode DC input be under 10 watts. Assume a K2
with the standard output transformer windings.

-- 
David Woolley
Emails are not formal business letters, whatever businesses may want.
RFC1855 says there should be an address here, but, in a world of spam,
that is no longer good advice, as archive address hiding may not work.
_______________________________________________
Elecraft mailing list
Post to: Elecraft at mailman.qth.net
You must be a subscriber to post to the list.
Subscriber Info (Addr. Change, sub, unsub etc.):
 http://mailman.qth.net/mailman/listinfo/elecraft    

Help: http://mailman.qth.net/subscribers.htm
Elecraft web page: http://www.elecraft.com