[Antennas] melting ice

[Bill Aycock]

I'm not sure what the question is. The voltage applied to a large loop IS 
the drop, and Ohms law will give the current; the current and Voltage will 
give the power .  Natural conditions will dictate how much of that heats 
the ice and how much is carried off by the air. The electrical part of the 
problem is the easy part.
Did I miss something?
Bill

At 09:44 PM 1/10/2005 -0600, Steve W0OOW wrote:

>Has anyone ever melted ice off of a loop using current?  I was wondering how
>much it took to melt ice.  I would suppose that the voltage drop would be
>pretty great with DC over a large loop, but IF enough voltage was applied to
>overcome the ohmic losses, how much current would it take to melt the ice.
>I suppose this depends upon the temperature as well.
>Thanks,
>Steve W0OOW
>CW - It's still magic !
>
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Bill Aycock - W4BSG
Woodville, Alabama