[AMRadio] AM power

[W2XJ]

But that is not the FCC definition of peak power.

On 6/18/11 10:55 PM, Gary Schafer wrote:
> Jeff,
>
> An easy way to prove this to yourself: set your scope on the output of your
> transmitter for say 2 divisions of carrier. Then modulate it with a single
> tone until the voltage on the scope doubles (4 divisions). That is 100%
> modulation I am sure that you would agree.
>
> Now remove the single tone and modulate with your voice until the voice
> peaks hit the same 4 divisions on the scope. You are now modulating 100%
> with your voice. Your peak envelope power is exactly the same with your
> voice as it was with the single tone. 4 times the carrier power.
>
> I urge you to carefully reread what I wrote in my long post on the subject.
>
> 73
> Gary  K4FMX
>
>> -----Original Message-----
>> From: amradio-bounces at mailman.qth.net [mailto:amradio-
>> bounces at mailman.qth.net] On Behalf Of Geoff Edmonson
>> Sent: Saturday, June 18, 2011 10:44 PM
>> To: Discussion of AM Radio in the Amateur Service
>> Subject: Re: [AMRadio] AM power
>>
>> On 06/18/2011 09:39 PM, Gary Schafer wrote:
>>> For those that wonder how PEP is found, you do so by adding voltages
>> in the
>>> carrier with the voltage in the applied audio. Since 100% modulation
>> is the
>>> doubling of the plate supply voltage which causes the plate current to
>> also
>>> double (2x2=4) this is where the 4 times PEP comes from.
>>>
>> Which is true if you're modulating the carrier with a single-tone
>> sinusoidal wave.
>>
>> that's not what comes out of our mouths.
>>
>> http://www.qsl.net/wa5bxo/asyam/aam3.html
>>
>> 73 = Best Regards,
>> -Geoff/W5OMR
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