[AMRadio] Dentron Clipperton on am?..

[Michael C. Marx]

Why not just use a good peak reading wattmeter and adjust the output to 1500 
watts PEP, no matter what the carrier power is?  Something like a LP-100A 
would be great for this (wish I owned one!)

However, I think that if you use the 4:1 rule, 160 watts carrier is the most 
you would want to run with 4 X 572B's given their 160 watt plate 
dissipation.  Any more than that with any reasonable transmission time will 
severely stress and shorten the life of the 572B's.  If you really blast 
them with air, you might get away with a little more......

Mike WB0SND


----- Original Message ----- 
From: "Kim Elmore" <cw_de_n5op at sbcglobal.net>
To: "Discussion of AM Radio in the Amateur Service" 
<amradio at mailman.qth.net>
Sent: Monday, April 11, 2011 8:42 PM
Subject: Re: [AMRadio] Dentron Clipperton on am?..


> Discussions like this are interesting and I hope not to open a can of
> worms, but I think the proof of any assertion like this lies within
> some estimate of the actual power in the side bands. That's where any
> signal that we want lies and it's what is detected. Has anyone done
> an analysis to show that more power is in the side bands one way than
> another? Any spectrum analysis or spectrum analyzer displays?
>
> 73,
>
> Kim Elmore N5OP
>
> At 05:26 PM 4/11/2011, you wrote:
>>On 04/11/2011 02:25 PM, John wrote:
>> > Ron, that assumes 100% modulation.  The rule never stated you had to
>> > run 100% modulation.  If you choose to run 100% modulation then you are
>> > correct, a 375 watt carrier with 100% modulation is your legal limit.
>> >
>> > John KX5JT
>> >
>> >> The rule states 1500w PEP output, regardless of mode.
>> >     From:  http://www.qsl.net/wa5bxo/amplitude-modulation-and pep.htm
>> >
>> >      "In the 375W carrier output example, this would mean 375 * 4 = 
>> > 1500W
>> > PEP."
>>
>>I put this in my previous message.  That statement is incorrect, John.
>>
>>http://www.qsl.net/wa5bxo/asyam/aam3.html
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