[SOC] Looking to build a Dummy (Load)

[Mike Besemer (WM4B)]

Just make sure the resistor is non-inductive.  A wire-wound won't do the
trick.

> -----Original Message-----
> From: soc-bounces at mailman.qth.net [mailto:soc-bounces at mailman.qth.net]
> On Behalf Of Tom McCulloch
> Sent: Thursday, January 22, 2009 9:31 PM
> To: Second Class Operators' Club
> Subject: Re: [SOC] Looking to build a Dummy (Load)
> 
> Carlos thanks...good point about needing only 40 watts to handle the
> 100
> watt load for a short time.
> 
> I think in parallel you divide and in series you add, though.
> 
> Thanks again
> 
> One guy pointed me one 50 ohm resistor at 100watts1  It only cost $9.50
> at
> Mouser, I think I;ll go that way.
> 
> Tom
> ----- Original Message -----
> From: "Carlos J Caro" <ccaro3 at juno.com>
> To: <soc at mailman.qth.net>
> Sent: Thursday, January 22, 2009 9:24 PM
> Subject: Re: [SOC] Looking to build a Dummy (Load)
> 
> 
> >
> >> 1) I guess I can figure out the value of 20 resistors I'd need to
> >> get a 50
> >> ohm result (well, maybe I can't.)  But what wattage should I use to
> >> handle
> >> 100 watts?  Am I going in parallel (yea, parallel, right? otherwise
> >> I'd need
> >> 100 watt resistors???, right?)  OK, so does that mean I'd need 20
> >> five watt
> >> resistors in parallel?
> >>
> > Tom,
> >
> > All your resistors will be in parallel so 50 ohms times 20 resistors
> > equal
> > 1000 ohms. If each resistor is 2 watts the load 1will be a 40 watt
> that
> > can handle the 100 watts for a short time.
> >
> >
> > Regards,
> >
> > Carlos K4REI
> >
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