[Rover] AC/DC Inverter question

[Mike KA5CVH Urich]

From: "Mike KA5CVH Urich" <ka5cvh@ka5cvh.com>

> numbers.  In your case a 700 watt load <based on my assumptions about
draw>
> really needs as a minimum a 700 <600*1.2=720w> watt inverter.  Now,


:-( Correction, the finished math is correct but I found a typo ... this
should have read :-(

> Soooo the Mike swag figure for inverters is arrived at by dividing 13.8 by
> 11.5 = 1.2.  Multiply your anticipated max load by 1.2 for safe real world
> numbers.  In your case a 600 watt load <based on my assumptions about
draw>
> really needs as a minimum a 600 <600*1.2=720w> watt inverter.  Now,
> furthermore, I personally don't want to push an inverter past 80% of its
> rated cacity for max draw, regardless of duty cycle, so, to give you a
> comfort zone of 15-20%  I would go ahead a swag that up to a minimum 800
> watts <720*1.2=864 watts> just to be on the safe side.

YMMV

Mike Urich,   KA5CVH
www.ka5cvh.com
LaPorte TX   EL-29

Amateur Radio *IS* a contact sport!