[R-390] Filters

Bob Camp ham at kb8tq.com
Tue Feb 19 20:33:27 EST 2013


Hi

If you have the RF power, all you need is a transformer / transformation to get the voltage. You could try for a straight transformer. I'd go with some sort of tuned circuit to do the multiplication. A pi network would also be a possible way to go. Cascaded L networks are the classic solution.  What ever it is, low Q is the way to go. You can easily get to high a Q and make it to twitchy to be useful. The problem with any single section approach is that the Q limits the maximum transform you can get.

Bob

On Feb 19, 2013, at 8:16 PM, quartz55 <quartz55 at hughes.net> wrote:

> Yes, didn't think about the 100K vs. 50 ohms.  So, 10VP-P @ 100K would be about 122uW.  That's do-able. But since db are db, 20log10/1(volts)=20db, so yes that would be about right if the filter has a 25db loss. Actually I should probably see about .6VP-P from 10VP-P.  That's easily seen on my 545A or B.
> 
> I'm not sure what my R2005 will put out in volts though.  Probably not 10P-P.  Maybe.
> ______________________________________________________________
> R-390 mailing list
> Home: http://mailman.qth.net/mailman/listinfo/r-390
> Help: http://mailman.qth.net/mmfaq.htm
> Post: mailto:R-390 at mailman.qth.net
> 
> This list hosted by: http://www.qsl.net
> Please help support this email list: http://www.qsl.net/donate.html



More information about the R-390 mailing list