[R-390] Capacitor calculation
Gord Hayward
ghayward at uoguelph.ca
Wed Jun 11 12:08:40 EDT 2008
>
>
>There is another issue with 3 terminal regulators that is important: TOO
>MUCH ripple can ALSO cause them to dissipate too much heat.
>
This is correct. The regulator has a minimum voltage where the
transistors drop out and the output voltage also drops.
For the 78xx series this is about 2.5 volts. There are newer low drop
out chips available. Too much ripple means that
the high end of the voltage cycle is too big so that shows up as heat
too. The best is to have the minimum slightly above
the drop out voltage - allow a bit for brown outs - and the maximum as
low as possible.
The capacitor calculation goes as follows:
RMS transformer voltage x 1.414 = peak then maximum voltage = peak -
0.7 (half wave) or peak - 1.4 (full wave)
Ripple voltage = maximum voltage - dropout voltage
Capacitor in Farads = (DC load current / Ripple voltage) x 1/60 sec for
half wave or 1/120 sec for full wave
I've neglected the conduction angle (time) - it works as a safety factor
in this calculation.
--
Gordon L. Hayward, Ph.D., P.Eng.,
Associate Professor, Biological Engineering,
School of Engineering, University of Guelph,
Guelph, Ontario, N1G 2W1.
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