[R-390] Using Surplus Meters in an R390A
Dennis Pharr
dpharr53 at swbell.net
Mon Aug 30 16:27:39 EDT 2004
Barry:
I had the same thought when I started building my version of the op-amp
circuit. I believe that by not having a resistance that simulates the meter
impedance it may upset the way the bridge circuit works. Although it may
not make a big difference, I installed an 18 ohm resistor across the input
to my version of the op-amp circuit. The op-amp then essentially just
amplifies the dc voltage drop across this resistor. With an 18 ohm resistor
shunting the input, the voltage seen by the op-amp is only about 18mv
(assuming a full scale 1ma reading), so the voltages you are dealing with
are quite small.
Actually, the way I understand op-amps, the combined resistance of the two
4.7K input resistors wouldn't make any difference anyway, since no current
flows into these inputs. Without the 18 ohm resistor, the op-amp circuit
would only amplify the voltage difference seen between the arms of the
bridge circuit.
Also, the 10K ten-turn pot used on the output of the Skirrow circuit is much
too large for effective use. I used a 1K ten-turn pot. This made it much
easier to set the sensitivity of the meter I used (5ma meter movement).
Good Luck
73
Dennis Pharr
WD5JWY
-----Original Message-----
From: r-390-bounces at mailman.qth.net [mailto:r-390-bounces at mailman.qth.net]
On Behalf Of N4BUQ at aol.com
Sent: Sunday, August 29, 2004 8:53 PM
To: r-390 at mailman.qth.net
Subject: [R-390] Using Surplus Meters in an R390A
I downloaded Jan's article about using surplus meters. Looking at the
schematic, it appears that inserting the OpAmp where the meter used to be
will
result in a minimun of 9.4K ohms where (according to what I remember posted
on this
list) the original meter's DC resistance is somewhere around 30 ohms.
Can someone comment on how/if this affects the performance in this part of
the radio? The text of the article indicate it is necessary to reset the
carrier meter adjust control for the proper readings. I assume that the
difference
of the resistance will cause this setting to be somewhat different than with
a
meter with 30 ohms resistance.
I haven't looked at the entire circuit yet and perhaps resetting the carrier
meter adjust control to compensate the difference in resistance causes the
circuit to become "normal" again, but not sure.
I have some replacement meters I am interested in using, but their internal
resistance is around 600 to 800 ohms so I was looking for a way to use them.
It appears Jan's method is easy enough, but I was wondering what the effects
are when using it.
Any comments?
Thanks,
Barry(III) - N4BUQ
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