[R-390] Exhumation of dead horse...Dead horse walking

[twleiper@juno.com]

On Fri, 11 Jan 2002 20:44:31 -0500 "rbethman" <rbethman@home.com> writes:
> > On Fri, 11 Jan 2002 15:32:18 -0500 "rbethman" <rbethman@home.com> 
> writes:
> > EDITED...mercifully
> > > Not so.  Power is not dependent on "time".  The power delivered
> > > during that pulse is full, not half.
> >
> > OK. Half the pulses, half the power. Forget the time. Same thing.
> >
> Tom,
> 
>     If the "pulse" is 26 Volts, and the current during this pulse is 
> two
> amps, that pulse is 52 watts - period!  Therefore, if the components 
> cannot
> stand that voltage, that current, or that amount of heat dissipation 
> - it
> DIES.  Now is when you factor in time, be it milliseconds, minutes, 
> or
> hours.

I see the problem...we are on the same side but speaking a different
language. I am talking about cumulative dissipation divided by time,
or avaerage power. As I said, the power delivered during that half
wave would be at twice the rated current, which the tubes MIGHT
be able to handle for a little while at a 50% duty cycle. But the
continous dissipation would also be too high as well, and the filaments
would still be running too hot. We agree.

Those that argue for the diode would probably think that if you could
somehow just eliminate nine of ten cycles, you could use ten times the
voltage... Maybe we could use twelve million volts for one microsecond
per second, wouldn't that deliver twelve watts continous?

Tom