[R-390] 6802 - and heat dissipation...

Rodney Bunt [email protected]
Mon, 7 Jan 2002 16:08:29 -0800 (PST)


The reason that the 6082's are HOT is that they are dropping the input voltage to 285v x the
current consumed by the R-390.

Therefore power dissipated is (325 - 285) * .3A = 12Watts.

This amount of heat would have to be dissipated in the "solid state regulator" anyway.

I agree that the heat from 4 filaments would not be introduced into the receiver with a solid
state regulator.

Remember that when the R-390 is in "standby" there is no current being drawn from the HT, so the
input voltage would rise to approx 360v+, that is 75v across the "collector - emitter" a big ask
for a Transistor, then again Power MOSFET could be used ....

PS: Just think of the ZENER chain to get 285v for the "series regulator" !!! Then again you could
use tubes for that!

Rodney Bunt
VK2KTZ


--- Barry Hauser <[email protected]> wrote:
> Richard wrote:
> > 6082's on the other hand...  I would not mind finding at least two of
> those
> > under a table some place.  It would be worth while to design a solid state
> > regulator for the R390 and put those hot and uncommon 6082's on a shelf.
> 
> Check out Issue #52 of the Hollow State Newsletter -- reversable SS mod for
> 6082's in the non-A.
> 
> Barry
> 
> _______________________________________________
> R-390 mailing list
> [email protected]
> http://mailman.qth.net/mailman/listinfo/r-390


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