[Milsurplus] Attention Smart People:

[Al Klase]

AGREED, the input/transformer-secondary must be floating lest one of the 
left-hand diodes be directly across the input.  My real problem is that 
I fail to see how this is going to double any voltage.  The negative 
sides of the caps in the bridge are always going to be one diode drop 
above ground, and therir positive ends are essentially in parallel, one 
diode drop above the output..

Al

On 8/3/2010 9:03 AM, arc5 at ix.netcom.com wrote:
> Please take a look at this full-wave doubler circuit:
>
> http://www.kwarc.org/bulletin/99-04/tech_corner.htm
>
> At the end of the page is this warning:
>
>      This circuit can be operated off the AC line 120 or 230 V).
>      BUT the negative ground must be left floating since
>      one side of the line Is grounded and YOU CANNOT ground
>      both the Input and the NEG (or POS) DC or else B O O M!
>
> I guess I'm stupid (I've only had one cup of coffee, so there's my excuse),
> because I don't see a current path from the DC B+ side
> to the AC line, other than ground which is supposed to be -0- potential
> on both sides.  Now, if your B- ground came loose on the power supply
> and you didn't have a grounded line cord installed
> (which would be even stupider than me with this kind of voltage)
> you'd have full B- on the chassis to ground and your wife
> would have to pay for a funeral.
>
> OK... what am I missing here?
>
>
> ______________________________________________________________
> Milsurplus mailing list
> Home: http://mailman.qth.net/mailman/listinfo/milsurplus
> Help: http://mailman.qth.net/mmfaq.htm
> Post: mailto:Milsurplus at mailman.qth.net
>
> This list hosted by: http://www.qsl.net
> Please help support this email list: http://www.qsl.net/donate.html
>    

-- 
Al Klase - N3FRQ
Jersey City, NJ
http://www.skywaves.ar88.net/