[Milsurplus] Boulevard Receiver

wf2u at ws19ops.com wf2u at ws19ops.com
Thu May 29 12:01:59 EDT 2008


Here is the filament data:

50L6 :   0.15A at 50V = 7.5W
25L6 :   0.3A at 25V  = 7.5W
6L6  :   0.9A at 6.3V = 5.67W

No big difference...

73, Meir WF2U
Landrum, SC


Quoting WA5CAB at cs.com:

> While I wouldn't disagree that a series dropping resistor in the filament
> string if present could generate more heat than a filament   
> transformer, 25 volt
> heater tubes generate no more (and no less) heat than their 12.6 or 6.3 volt
> equivalents.  In this particular case, my take is that the 25L6 (and 50L6)
> should have been called something else.   They aren't really 25 or   
> 50 volt 6L6's.
> But for the purposes of this thread, their heater wattage is close   
> to the same
> as that of the 6L6.  Which means about the same heat generated per tube, not
> double or quadruple.
>
> In a message dated 5/28/2008 11:36:17 PM Central Daylight Time,
> kargo_cult at msn.com writes:
>> ( My main problem with the AC-DCs is that they almost always have some
>> dropping resistors inside them, which generate heat, plus the high-filament
>> voltage tubes such as 25L6 etc. all of which generate more heat. )
>
> Robert Downs - Houston
> <http://www.wa5cab.com> (Web Store)
> MVPA 9480
> <wa5cab at cs.com> (Primary email)
> <wa5cab at comcast.net> (Backup email)
>
>




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