[Milsurplus] Leakage in Electrolytics

[Don Davis]

Not really.  DC leakage is dc, and the voltage is dc.  This is the resistive
portion of the capacitor in shunt with the capacitor.  It is strictly an E x
I function.    My opinion:  2 mA is excessive, and the cap is worthy of
replacement.

In addition, there is an ESR (Equivalent Series Resistance) that will
dissipate due to an ac current flowing through the capacitor.  It is an
I(ac)**2 x R x cosine(o) factor.  This is probably what you're thinking of.
Can also be very large, and lead to early failure.

Don  AD6PB


----- Original Message ----- 
From: "James Duffer" <dufferjames at hotmail.com>
As I recall there
> is a phase angle between capacitor current and the voltage producing the
> capacitance current.  watts=I x E x PF.  Power Factor (PF) being the
cosine
> of the phase angle.  We can't forget Eli the Ice man.
>
> 73, de wd4air