[Milsurplus] Leakage in Electrolytics

[James Duffer]

snip
> > In addition to the other comments, remember that 2 ma. times, say, 300 
>volts is 6 tenths of a watt.  Not much until you consider it is buried 
>inside the capacitor, and has to get out through a less than excellent 
>thermal path
73,
George
> > W5VPQ

The question comes to mind------is it really  .6 watts??  As I recall there 
is a phase angle between capacitor current and the voltage producing the 
capacitance current.  watts=I x E x PF.  Power Factor (PF) being the cosine 
of the phase angle.  We can't forget Eli the Ice man.

73, de wd4air