[Lowfer] Ferrite Loading Coil ?

Pete Cranwell pete at pcranwell.com
Tue Feb 12 08:25:41 EST 2008


I guess what I'm trying to say is that unless there is current flow in the
coil you cant generate any flux.  Current flow is determined by applied
voltage and complex impedance (wire losses, core losses etc).  Have I missed
something?  Isn't magnet flux generated when electrons move through a wire &
EMF is generated when magnet flux cuts a wire ?

Cheers

Pete

-----Original Message-----
From: lowfer-bounces at mailman.qth.net
[mailto:lowfer-bounces at mailman.qth.net]On Behalf Of jrusgrove at comcast.net
Sent: Tuesday, February 12, 2008 7:27 AM
To: Discussion of the Lowfer (US, European, & UK) and MedFer bands
Subject: Re: [Lowfer] Ferrite Loading Coil ?


Bmax = Epk X 10^2 / 4.44 x Ae x N x f

Epk = peak rms voltage
Ae = cross sectional area in cm^2
N = number of turns
f = frequency in MHz

Jay





----- Original Message -----
From: "Pete Cranwell" <pete at pcranwell.com>
To: <evp at pacbell.net>; "Discussion of the Lowfer (US, European, &amp"
<lowfer at mailman.qth.net>
Sent: Tuesday, February 12, 2008 7:04 AM
Subject: RE: [Lowfer] Ferrite Loading Coil ?


>I = E/R
>
> -----Original Message-----
> From: lowfer-bounces at mailman.qth.net
> [mailto:lowfer-bounces at mailman.qth.net]On Behalf Of Ed Phillips
> Sent: Monday, February 11, 2008 7:49 PM
> To: Discussion of the Lowfer (US, European, &amp; UK) and MedFer bands
> Subject: Re: [Lowfer] Ferrite Loading Coil ?
>
>
> In receiving you don't have high currents therefore you won't saturate a
> core in receiving applications"
>
> The flux density in the core doesn't depend on the current.  It's
> proportional to the voltage across the coil and inversely proportional to
> core area and number of turns.
>
> Ed
>
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