[Laser] Beacon to test a photodetector sensitivity limit
Art
KY1K at verizon.net
Sun May 20 13:29:27 EDT 2007
I couldn't agree more Terry!
I never tried using a 1N914 diode as a photon source though. I have
tried only old technology LED's.
But, I always STRONGLY suspected that IR or other wavelength photons
were being produced by the LED's at low current levels. I did not try
an IR absorbing filter to confirm this, mainly because I didn't have
one at the time.
I started out working with red LED's at 10-100 microamps and found
they totally swamp any sensitive light receiver-too many photons and
had very very poor linearity! It was VERY BAD. Varying the number of
photons out by varying the curret to the LED was very un-linear at
these lower current levels.
From this point, I decided to use a highly sensitive PM tube for
setting the output of the LED to a relative level-then switching to
the DUT to take measurements. Even this didn't work! What I found was
that the relative output of the photomultiplier didn't correlate to
the readings taken by the DUT!
I concluded that the LED must be producing near IR-which the
photodiode was sensitive to and the PM tube wasn't....hence the non
correlation between the PMT and DUT relative outputs.
The ONLY way I could make this work was to run the LED between 5 and
30 ma and to use a pinhole in combination with a series of absorbers
between the pinhole and the PMT/DUT. Using this method, I got
excellent correlation between the PMT and the DUT outputs. But, the
LED still wasn't very linear. I was happy enough though because I
could get a weak signal to evaluate the various photodiode amps I was
working with.
>>With our last photodetectors, we noticed it is possible to hear the signal
>>to 1 meter without lens while it is absolutely not possible to see the LED
>>with eyes.
Yves, please BEWARE of evaluating a photodiode without a lens!
Without a lens, that photodiode will pick up photons from almost any
angle. You need a lens or some method of limiting the angle of
admittance of the photons entering your detector. Without it, you
will have scattered photons and very much distorted sensitivity
data-the detector will seem much more sensitive than it really is.
To test this, go into your dark room and take a reading of the
ambient light level with a lens in front of the PD, without a lens
over the PD and with the PD in total darkness (covered with a light
shield). You will find the ambient light level to be several 10's or
hundreds of times higher without the lens-because the few photons
that find your way onto the dark room are bouncing around off of
every single wall surface in the room and there is allot of
reflecting area! Even with the lens in your dark room, you will
probably detect a small amount of light compared to the readings
obtained with the covered photodiode.
The only way I found around this problem was to mount the photodiode
in a black box surrounded by flat black 'flocking' paper and to have
a pinhole several inches in front of the photodiode-the only light
allowed to reach the PD was through the pin hole. Even then, the
electronics had to be totally shielded from light because solder and
copper etches reflect stray light that enters the pinhole from
extreme angles. For high sensitivity detectors, the detector
shielding from RF and EMF also blocks light, so it's not a problem.
But, do be aware you have to wrap the metal shielding in flocking
paper to prevent it from reflecting stray photons.
It's a very long story, and I won't bore you with ALL the details.
The short version is that I eventually migrated to my landlords
basement in the apartment building to do optical testing. It was in
the lower basement, 20 feet below ground level and there were no
windows or way for light to enter the room although it was a large
open area with lots of junk in the room. I went to this area
expecting it to be pitch black so I wouldn't have to worry about
stray light. But, using a photodiode without a lens, it was painfully
obvious that light was getting in somehow (the ambient light level
was 5 to 15 millivolts while the dark level (with a cover over the
PD) was well under 1 millivolt. I started using my receiver as a
probe to find out where the light was coming from. Basically, light
was coming from everywhere, even off my hand placed a few inches in
front of the photodiode! There was absolutely no visible light
anywhere in the room that I could detect with my eyes. Poking around
in pitch black was not easy, but I eventually found a peak-coming
from the furnace room door direction. In this room, there was an LED
on the furnace. I assumed this to be the source of my light even
though it was in the next room with the door closed. Even with this
LED completely covered, and the door to the furnace room closed and
taped over, I still got residual light levels in the basement area
until I put a pinhole over the PD to minimize the admittance angle
that of the PD's view.
With the lesson learned here, I eventually was able to build a test
setup that allowed me to work in my kitchen (at night with the lights
turned off). It was much more convenient this way!
I ended up with a medium sized cardboard box lined with flocking
paper with a shoe box lined with flocking paper inside of it. All the
optics were inside the shoe box. My light source was an LED covered
in rubber cement and painted black except for a small pinhole to let
some of the LED's light out.
Between the light source and the PD was anywhere from 1 to 5 pieces
of arc welding light absorbing glass with a pin hole on the PD side.
In order for it to work, it was necessary to wrap the arc welding
absorbers in flocking paper in order to keep the reflections from the
glass surface from contaminating the readings (by reflecting the
little bit of stray light inside the enclosure).
Eventually, I just left the LED running at 5 ma and varied the number
of absorbers between the LED and the PD to get my weak signals. It
was all 'relative', but it was cheap, and it worked well.
Regards,
Art
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