[ICOM] IC-7000 AM Modulation Problem
w8okn at charter.net
w8okn at charter.net
Fri Apr 7 16:49:10 EDT 2006
Absolutely.
- D C *Mac* Macdonald <k2gkk at hotmail.com> wrote:
> To calculate dB for Voltage or Current
>
> * Va
> * dB = 20 log ------
> * Vb
>
>
> OR
>
>
> * Ia
> * dB = 20 log ------
> * Ib
>
>
> To calculate dB for Power
>
> * Pa
> * dB = 10 log ------
> * Pb
>
>
> The result WILL be the same for a given
> circuit, assuming linear operation of that
> circuit.
>
> 73 - Mac, K2GKK/5
> Oklahoma City, OK
>
>
>
> ----Original Message Follows----
> From: <w8okn at charter.net>
> To: ICOM Reflector <icom at mailman.qth.net>
> CC: D C *Mac* Macdonald <k2gkk at hotmail.com>
> Subject: Re: [ICOM] IC-7000 AM Modulation Problem
> Date: Fri, 7 Apr 2006 12:49:20 -0700
>
> DB is simply a method of comparison based on logarithm
> if I recall my EE math.
>
> The logarithm of any given number is the exponent of a
> power to which another given invariable number, called
> the base, must be raised in order to produce that given
> number. Thus, let 10 be the base, then 2 is the logarithm
> of 100, because 10^{2} = 100, and 3 is the logarithm of
> 1,000, because 10^{3} = 1,000.
>
> So, 10 to the 3rd is therefore 2x. 3db gain (or differential
> perhaps might be easier to think about) is a comparison of
> one value to another, in simple terms. 3 dbd would then be
> 2x over a dipole.
>
>
>
> ---- D C *Mac* Macdonald <k2gkk at hotmail.com> wrote:
> > dB ARE dB. They are identical in absolute quantity.
> > The difference is that they are derived differently for
> > voltage, current and power. The formulas for computing
> > dB are different, but the absolute difference in dB between
> > two signals will be the same if calculated with the correct
> > formula.
> >
> > Application of Ohms Law will show that doubling the
> > applied voltage will also double the current, resulting in
> > quadrupling of the power. Figure dB change for any
> > of these three specific quantities with the correct
> > formula will give the same result.
> >
> >
> > Mac - K2GKK/5
> >
> >
> >
> > ----Original Message Follows----
> > From: C Whitaker <whitaker at pa.net>
> > Reply-To: ICOM Reflector <icom at mailman.qth.net>
> > To: ICOM Reflector <icom at mailman.qth.net>
> > Subject: Re: [ICOM] IC-7000 AM Modulation Problem
> > Date: Fri, 07 Apr 2006 14:20:06 -0400
> >
> > de WB2CPN
> >
> > I wonder if we get confused when we're calculating
> > dB when we don't consider whether it's Voltage dB
> > or Power dB, there being considerable difference in
> > the numbers.
> >
> > 73 Clete
> >
> >
> >
> >
> > ----
> > Your Moderator: Dick Flanagan K7VC, icom-owner at mailman.qth.net
> > Icom Users Net: Sundays, 1700Z, 14.316 MHz
> > Icom FAQ: http://www.qsl.net/icom/
> >
> >
> > ----
> > Your Moderator: Dick Flanagan K7VC, icom-owner at mailman.qth.net
> > Icom Users Net: Sundays, 1700Z, 14.316 MHz
> > Icom FAQ: http://www.qsl.net/icom/
>
>
> ----
> Your Moderator: Dick Flanagan K7VC, icom-owner at mailman.qth.net
> Icom Users Net: Sundays, 1700Z, 14.316 MHz
> Icom FAQ: http://www.qsl.net/icom/
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