[Ham-Computers] Need information.

[Dan Violette]

BUT the original solution is already 35% (can't get 100% peroxide, and only
special approval purchase will get you 70%).  So you need about 1/3 of the
water listed by Loren (31/3 = 10 1/3 water).  Which is why I said 1 Peroxide
to 10 Water.  Gets more complicated to try to explain in writing.  That's
why I could never write a textbook.  Dan KI6X

-----Original Message-----
From: ham-computers-bounces at mailman.qth.net
[mailto:ham-computers-bounces at mailman.qth.net] On Behalf Of Loren Moline
WA7SKT
Sent: Monday, December 26, 2011 2:14 PM
To: ham-computers at mailman.qth.net
Subject: Re: [Ham-Computers] Need information.


Ken,

I think you need more water.
Take this example.: if you had 3 cups of 33% solution that would be as 1 cup
of 100% and 2 cups of water.

so you retain the original figure of 1 cup of 100%

1 cup of 100% to 30 cups of water would be total of 31 cups.

1/31=3.2%

Since you already have 2 cups of water mixed with your 1 cup of concentrate
you need 30 cups of water - 2 cups or 28 cups of water.

You now have your original 1 cup of 100% plus 30 cups of water...

Am I making sense?

 
Loren   WA7SKT
 
Member: ARRL and Pacific Northwest VHF Society
Member: Hearsat Satellite Monitoring Group ( www.hearsat.org )
Location: CN86bx

                          
                                 







> From: n5cm at rtconline.com
> To: ham-computers at mailman.qth.net
> Date: Mon, 26 Dec 2011 15:18:31 -0600
> Subject: Re: [Ham-Computers] Need information.
> 
> Hi Dan,
> 
> Many thanks for the info!
> 
> Now, if I mix 1 part 35% with 10 parts h2o (clean water), I should get 
> close to 3.5% solution so if I add a bit more of h2o, I should come 
> close to 3%.  I'll try that!
> Thanks!
> 
> It is for internal use therefore the caution.  Too much h2o2 (hydrogon
> peroxide) can kill!
> 
> Ken   N5CM
> 
> 
> 
> 
> 
> 
> 
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