[Ham-Computers] Need information.

[Dan Violette]

Actually the "concentrate" is 35% in your example.  Loren was using 100% as
the concentrate.  So, to get close (not exact but close enough)

To get 3% divide the two 35/3 = about 11 (total parts)

1 part 35% concentrate + 10 parts water = 11 parts of 3.18% (35/11, close
enough to 3%)

1 part 35% + 3 parts water = 8.75% (35/4 parts) [1 part of 35% + 3 3/8 parts
water to get 8%, (35/4.375 = 8)]

Now, I think I have that correct?

/Dan KI6X

-----Original Message-----
From: ham-computers-bounces at mailman.qth.net
[mailto:ham-computers-bounces at mailman.qth.net] On Behalf Of Ken
Sent: Monday, December 26, 2011 5:43 AM
To: boatanchors at mailman.qth.net; boatanchors at theporch.com;
ham-computers at mailman.qth.net
Subject: [Ham-Computers] Need information.

Hi Folks,
Please excuse but I desperately need information. My math ain't what it used
to be!

Can someone tell me how to mix 35% solution with clean water to get a 3%
solution. 
I bought a quantity of "food grade 35% solution  h2o2 and need the 3%
solution. 
While at it, how about a 35% solution down to an 8% solution for agricultral
purposes?
My heartfelt thanks. My math never was anything to brag about and far worse
now tho I am only 94 years of age!

Ken  N5CM




=======
Email scanned by PC Tools - No viruses or spyware found.
(Email Guard: 7.0.0.18, Virus/Spyware Database: 6.18940)
http://www.pctools.com/ =======
______________________________________________________________
Ham-Computers mailing list
Home: http://mailman.qth.net/mailman/listinfo/ham-computers
Help: http://mailman.qth.net/mmfaq.htm
Post: mailto:Ham-Computers at mailman.qth.net

List Administrator: Duane Fischer, W8DBF
** For Assistance: dfischer at usol.com ** 


This list hosted by: http://www.qsl.net
Please help support this email list: http://www.qsl.net/donate.html