[Elecraft] Slightly OT: non-resonant wires

[Fred Jensen]

http://www.engineeringtoolbox.com/cable-loads-d_1816.html

A wire supported at the ends and loaded uniformly only by its own weight 
will form a catenary, and mid-span sag is a function of mid-span 
tension.  Zero sag = infinite tension.  Unfortunately, center-fed 
dipoles are not uniformly loaded.

Just lay the wire out on the ground in a straight-ish line and measure 
it.  I use a 50' steel tape.  Lots of things will affect its ultimate 
electrical length when installed, you'll need to prune it some anyway. 
I just fold the ends back on the wire until I've got the right length 
and then cut it and belay it to the insulator(s).

73,

Fred K6DGW
- Northern California Contest Club
- CU in the Cal QSO Party 1-2 Oct 2016
- www.cqp.org

On 2/9/2016 12:22 PM, Bob McGraw K4TAX wrote:

> The only challenge is to estimate
> the wire sag in measuring a long length of wire.