[Elecraft] Considering a KPA-500
Fred Jensen
k6dgw at foothill.net
Sat Apr 25 13:28:22 EDT 2015
Interesting idea, pretty hard to read. If it had columns to start with,
they went away in the email for me -- maybe not for others. The real
measure is $US/dB gained at the other end, but see below.
dBm is power in dB referenced to 1 mW. 1mW=0 dBm. 1W=+30 dBm.
100W=+50dBm. 700W [KPA500 full bars]=+58.45dBm. 1500W=+61.76 dBm
With larger powers measured in watts, it is common to use dBW -- power
in dB referenced to 1 watt. 1W=0dBW. 100W=+20dBw. 700W=+28.45dBW.
1500W=+31.76dBW. dBW=10*log(power), which is a tad simpler.
1 S-unit is [nominally] 6 dB with S9=50uV at receiver input. If the
input Z is 50 ohms, that equates to -73 dBm.
$US per S-unit at the other end sort of says it. Would be interesting
to see what the $US per S-unit is for various antenna arrangements.
There is also a "panadapter gain" [similar to "coding gain"] in that
being able to watch the whole pile-up lets you find the guy he just
worked and gives you an advantage, in dB. If you live in the middle of
the country, there is a "Stepp-ir gain" in that you can reverse that
antenna almost instantly in a contest. I don't know how to quantify P3
gain or Stepp-ir gain however. :-)
73,
Fred K6DGW
- Northern California Contest Club
- CU in the 50th Running of the Cal QSO Party 3-4 Oct 2015
- www.cqp.org
On 4/24/2015 11:48 PM, Nick - VE3EY wrote:
> In addition to conventional "$ per watt" breakdown, I have also included
> "$ per dBm". It basically tells you how much each additional decibel of
> gain over 100 watt output power will cost you based on the estimated power
> output , purchase price and gain as compared to your typical barefoot rig.
>
> For power output I have made some rough estimates as to how much power a
> given amplifier can produce. The prices I have collected today from
> various vendor or dealer web sites. May not be entirely accurate but you
> get an idea.
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