[Elecraft] CQ WW CW & a K3

[Fred Jensen]

Vic K2VCO wrote:
> hank k8dd wrote:
> 
>> Let's say I am listening to 1830.000 to a DX station.  VFO A
>> The DX station says QSX 1829 so I set VFO B to 1829.00
>> The RIT is on and is + 1 KHZ - so A reads 1830.100
>> Now I want to listen to the pile on the TX frequency, so I press REV.
>> Now my TX freq reads 1829.100 and my RX freq on the bottom reads 1830.00
>> I find where the last station worked is and release the REV button.  The
>> TX freq is going to be 100 Hz low!
>> Seems to me that the RIT should stay with the frequency and not the 
>> location of that frequency.
>> As I saw it this afternoon that could cause me to not be on the TX 
>> frequency where I want to be transmitting.
> 
> I'm assuming that you did have SPLIT on and that you meant that the RIT 
> was set to +100 Hz, not +1 kHz.
> 
> You're right that the K3 thinks of RIT as part of VFO A. And note that, 
> unlike some other rigs, you can't choose to receive on VFO B -- you 
> always receive on A and you have a choice to transmit on A or B (of 
> course, you can copy the frequency from B to A and then receive on it; 
> but you are still using VFO A to receive.
> 
> What you did is a funny scenario, since if you were using split, you 
> would tune the DX station with VFO A and not use RIT. RIT would not help 
>  in this situation.
> 
> If the RIT "stayed with the frequency" then when you pressed REV, A 
> would read 1829 and B would be 1830.1. This is probably harmless with 
> REV, since you wouldn't operate the RIT while holding it. But suppose 
> you did A/B. Then what would happen when you clear the RIT? Should B go 
> back to 1830? Should A go to 1828.9? Should A/B work differently in this 
> respect than REV?

Wow!  And I thought partial differential equations was hard to 
understand ;-)

73,

Fred K6DGW
- Northern California Contest Club
- CU in the 2008 Cal QSO Party  4-5 Oct 08
- www.cqp.org