[Elecraft] K2 power output measurement accuracy?

[Darwin, Keith]

Ya lost me there Larry.  P = E^^2 / R.  R is 50 ohms, P is 10 watts, E
works out to sqrt(500) or 22.36 volts.  But are we talking RMS, peak, or
peak-to-peak?

Let's see, if my number is an RMS and you're number is peak, then 22.36
is about 22.4.  Multiply by 1.41 and I get 31.6  Pretty close to your
number.

Or am I way off base?

- Keith -

-----Original Message-----
From: Larry Phipps [mailto:larry at telepostinc.com] 

It's a standard diode peak detector I believe, so it would indicate 31.7
VDC (minus the drop) at 10 W for a 50 ohm load. I expect the drop is
about 0.3 V.


Darwin, Keith wrote:

> I never completed the RF probe with the K2 (didn't need it).  I assume

> it simply converts RF AC voltage into DC voltage (probably RMS) so you

> can measure it with a DVM, right?  So at 10 watts into a dummy load, I

> should see 22.4 volts?  Does the diode drop some voltage so I'll 
> actually see 21.7?