[Elecraft] how did I calculate the loss?

[drcuthbert@micron.com]

You might be wondering how I calculated the line loss with the =
mismatched load. I used two methods. NEC (with a physical T-line) and =
with WinSmith. But, I remembered a link to an online program that easily =
solves this type of problem. Here is the link: =
http://fermi.la.asu.edu/w9cf/tran/
 =20
Let's solve the 30 -j500 ohm load with 180 feet of RG213:                =
             Loss =3D 9.7 dB=20
Let's solve the 30 -j500 ohm load with 270 feet of 450 ohm ladder ohm =
line:    Loss =3D 2.8 dB
Let's solve the 30 -j500 ohm load with 270 feet of 600 ohm opn line:     =
          Loss =3D 0.9 dB

Not that bad with 600 ohm line. Less line length means less loss (it's =
not linear though). And with 600 ohm line we don't have to avoid any =
line lengths to avoid an awkward impedance at the K2, as we might have =
to with 50 ohm line. For example, a 45 degree, 600 ohm line (68 feet) =
gives 10 +j50 at the K2 and only 0.42 dB of line line. I am now of the =
opinion that feeding the 8030 with open line, and tuning with the K2, is =
a viable option.

    Dave WX7G=20