[CW] CW Duty Cycle Question

[Joe L Blackwell]

Somehow I knew this was coming next.
73, Joe, aa4nn
 
> > For plain-language English text, about 44%.
> >
> 
> Lets see, we have previously determined bandwidth of a CW signal is 
> mainly
> determined by rise and fall times of the keying.  So if we optimize 
> rise and fall
> times just short of causing key clicks, that will allow us to use 
> the narrowest
> filter possible.
> 
> Now we see that the duty cycle is less than 50 percent so we can run 
> our rigs at
> twice the rated maximum without hurting them.
> 
> What I am looking for now is a request for help from someone who let 
> the smoke out
> of his transmitter while trying to find his signal on a receiver 
> using a very narrow
> filter.
> 
> Regards,
> Frank Kamp
> K5DKZ
> 
>