[CW] CORRECTION - Speed vs Bandwidth

Sun, 14 Mar 2004 23:16:48 -0600

David, what is the assumed waveshape?

73, George W5YR
Fairview, TX
[email protected]
http://www.w5yr.com

----- Original Message ----- 
From: "David J. Ring, Jr." <[email protected]>
To: "David J. Ring, Jr." <[email protected]>; <[email protected]>
Sent: Sunday, March 14, 2004 11:02 PM
Subject: [CW] CORRECTION - Speed vs Bandwidth

> I just started to reread through I wrote, and I found at least one error.
>
> 60 wpm produces 25 dots and 25 inter-element spaces (50 total code
elements)
> in sixty seconds.  Each dot or each inter-element space occupies 1/50 of a
> second or 20 ms.
>
> That should read:
>
> 60 wpm produces 25 dots and 25 inter-element spaces (50 total code
elements)
> PER second.  Each dot or each inter-element space occupies 1/50 of a
> second or 20 ms.
>
> Of course at 60 wpm, we would produce 25*60=1,500 dots in a second but I
> think you'll agree it is much easier to count the dots in one second (25)
> than to count the dots in one minute (1,500).
>
> 73
>
> David who is going back to dot counting.
>
>
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