[Boatanchors] Fw: Slightly OT: What is the optimum "twist ratio" in window-line

Jim Wilhite w5jo at brightok.net
Sat Nov 19 23:13:05 EST 2011


----- Original Message ----- 

Mac you hit the nail on the head.  The purpose of the twist is
resistance to air flow not radiation nor pickup of extraneous signals.
If you have an interfering signal, it won't care what orientation the
feedline is.  One, obviously, does not want to twist the line
excessively, that can cause problems.  The amount you suggest is good.

Jim/W5JO
> ----- Original Message ----- 
>
>>
>> I generally use a full twist around 8 feet. Somewhere,
>> there is probably some sort of formula that is based
>> on the wavelength at the highest frequency being used
>> on that feedline.
>>
>> I am more concerned about flutter and accompanying
>> fatigue of the conductors in high Oklahoma winds than
>> I am about any radiation or pickup considerations.
>>
>> * * * * * * * * * * *
>> * 73 - Mac, K2GKK/5 *
>> * (Since 30 Nov 53) *
>> * Oklahoma City, OK *
>> * USAF, Ret (61-81) *
>> * * * * * * * * * * *
>>
>>
>>
>>> Date: Sun, 20 Nov 2011 00:16:38 +0000
>>> From: ko6bb1 at gmail.com
>>> To: boatanchors at mailman.qth.net
>>> Subject: [Boatanchors] Slightly OT: What is the optimum "twist 
>>> ratio" in window-line
>>>
>>> I'm asking this here as I don't belong to any antenna lists right 
>>> now.
>>>
>>> If you were using 450 Ohm window-line to feed a dipole, and you 
>>> wanted
>>> to minimize stray radiation or extraneous pickup from the line, 
>>> about
>>> how many twists (say per 10 feet of line, or whatever) would you put 
>>> in it?
>>>
>>> Thank you.
>>>
>>> -- 
>>> 73 de Phil, KO6BB



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