[Boatanchors] Need information.

[jmfranke]

First, determine how much h2o2 is in the original solution. Let the volume 
of the original solution be V. Then the amount of h2o2 is 0.35V. You want an 
end volume having 0.03 h2o2 and you have 0.35V of h2o2. The final volume 
will be called X. 0.35V = 0.03X or X = (0.35/0.03) V. X = 10. So mark a 
volume of 10V, pour in your present solution, add water until you have 10V 
and there you are! For the 8% case. X = (0.35/0.08) V. X = 4.375 V.

John  WA4WDL

--------------------------------------------------
From: "Ken" <n5cm at rtconline.com>
Sent: Monday, December 26, 2011 8:42 AM
To: <boatanchors at mailman.qth.net>; <boatanchors at theporch.com>; 
<ham-computers at mailman.qth.net>
Subject: [Boatanchors] Need information.

> Hi Folks,
> Please excuse but I desperately need information. My math ain't what it 
> used to be!
>
> Can someone tell me how to mix 35% solution with clean water to get a 3% 
> solution.
> I bought a quantity of "food grade 35% solution  h2o2 and need the 3% 
> solution.
> While at it, how about a 35% solution down to an 8% solution for 
> agricultral purposes?
> My heartfelt thanks. My math never was anything to brag about and far 
> worse now tho I am only 94 years of age!
>
> Ken  N5CM
>
>
>
>
> =======
> Email scanned by PC Tools - No viruses or spyware found.
> (Email Guard: 7.0.0.18, Virus/Spyware Database: 6.18940)
> http://www.pctools.com/
> =======
> ______________________________________________________________
> Boatanchors mailing list
> Home: http://mailman.qth.net/mailman/listinfo/boatanchors
> Help: http://mailman.qth.net/mmfaq.htm
> Post: mailto:Boatanchors at mailman.qth.net
>
> List Administrator: Duane Fischer, W8DBF
> ** For Assistance: dfischer at usol.com **
>
>
> This list hosted by: http://www.qsl.net
> Please help support this email list: http://www.qsl.net/donate.html
>