[Boatanchors] More question on US AC voltage

[Ian]

Not quite...

Try this:

100 volts across 100 ohms.

P = (100 x 100) /100 = 100 watts

Raise voltage 4% to 104 volts


104 volts across 100 ohms.

P = (104 x 104) /100 = 108.16 watts


So in this case 4% increase in voltage produces just over 8% increase in
power

So you can't just decide that a 4% increase will be squared to 16%.

Maybe this is just an example of "Figures can lie!"   <chuckle>

Your conclusion however is correct that increase the voltage, increase the
power and get more revenue.

Ian, K6SDE



-----Original Message-----
From: boatanchors-bounces at mailman.qth.net
[mailto:boatanchors-bounces at mailman.qth.net] On Behalf Of Larry Kirkland
Sent: Friday, February 10, 2006 8:53 AM
Cc: boatanchors at mailman.qth.net
Subject: Re: [Boatanchors] More question on US AC voltage

Don't you think it is in the monetary interest of the electric utilities 
to keep the supplied voltage on the high side of nominal?  If I recall 
Ohm's law correctly, as voltage goes up, power increases as the square 
of voltage (P = E squared /R).  In other words, as an example, if the 
voltage is raised 4%, the power consumed will increase 16% assuming R 
remains constant.  Increased consumption = higher power bills = 
increased operating profits.

Larry W4LK
_______________________________________________
Boatanchors mailing list
Boatanchors at mailman.qth.net
http://mailman.qth.net/mailman/listinfo/boatanchors
** List Administrator - Duane Fischer, W8DBF/W9WZE **   
** For Assistance: dfischer at usol.com **         
$$ For vintage radio info, see the HCI web site $$      
http://www.w9wze.org