[ARC5] Plate impedance...

[w7qho]

On Dec 14, 2008, at 8:59:32 PM, "Kenneth G. Gordon" <kgordon2006 at verizon.net> wrote:
>  A rigorous
> answer to this would require knowing the operating conduction angles
> and access to constant current curves for the tubes.  An approximate
> answer would be 550 divided by 0.15 as mentioned by Robert.

That is for DC. For AC, one formula used is plate voltage divided by 
twice the plate current.

Plate current divided by twice the plate current is an impedance approximation for Class B linear amps, not Class C.

--
Dennis D.  W7QHO
Glendale, CA
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