[Antennas] mfj -260c dummy load

[Ray Brown]

----- Original Message ----- 
From: "G B" <microsys at alltel.net>

> I was going to cut some 2M baluns with this dummy load, and it shows 1.2 to
> 1 swr.
> Then I measured it with my digital meter and read 53.4 ohms.  I got a 1%
> 49.9 ohm resistor and it measured 49.8 ohms.
>
> So, has anyone else noticed this, and, is there a way to adjust it to the
> proper resistance?

  Haven't really noticed, but yeah it'd be fairly easy to correct this, if you really
want to go to the trouble... let's see. It's the (R1 x R2) / (R1 + R2) problem,
so to solve for 52.0,  you would need to parallel a resistor with the value of
about 2k. Now, wattage-wise, of course, the lion's share of the power will
still go thru the 53.4 resistor, but it's been too long since I figured power
division, so that should be at least a 5 watt resistor, to err on the safe side.
If someone else wants to do the power divider, go for it...

  One thing to make certain, though, is to use a good multi-meter that has the
triangle, or delta, key. Most good Flukes have this. It allows the meter to
deduct the resistance of the lead wires themselves. You might find that your
power resistor might read closer to 52.0 than you thought. :-)

  Have fun! :-)

                _Ray_        KBØSTN