[Antennas] antenna trivia quiz for the day
Dave Shrader
[email protected]
Sun, 16 Jun 2002 19:42:22 -0400
Don't think so!
Using the components of two identical tuners; i.e. taking the 2
inductors and connecting them in series, and taking the capacitors and
connecting them in parallel will produce a resonant circuit at 1.8 MHz.
Fo = 1/(2*pi*(sqrt 2*l*2*C)) = 1/(4*pi*(sqrt L*C)).
It is possible to construct a 'new' tuner using the components by
suitable series parallel connections.
But, this is not the case you define. If I connect the second [output]
tuner to a 100 ohm dummy load and tune it to 3.6 MHz I will see a 50 ohm
match looking into the tuner. The first tuner will see a fifty ohm load
at 3.6 MHz and no linear system with a 3.5 MHz lower limit is going to
convert a 50 ohm load at 3.6 to a 50 ohm load at 1.8 MHz with the range
of values in typical 80 - 10 meter tuners.
You have in effect two series connected circuits with a lower frequency
limit of 3.5 MHZ.
Deacon Dave, W1MCE
rb wrote:
>
> OK, let's have some chatter on the reflector. Trivia question for the day
> just might generate some discussion.
>
> Assume we have a mix of any two commercial common small antenna tuners which
> are designed to handle up to 300 watts or so, unbalanced, on 80-10m either
> of which will load into an antenna well on 80-10m with 100 watts.
>
> If we put these two tuners in series with each other, will we have a rig
> which will enable us to tune 160m?
>
> Why or why not? Think about it.
>
> - - -
>
> Your moderator for this list is:
> Larry Wilson KE1HZ [email protected]
> _______________________________________________
> Antennas mailing list
> [email protected]
> http://mailman.qth.net/mailman/listinfo/antennas