[AMRadio] AM power

[Gary Schafer]

Jeff,

An easy way to prove this to yourself: set your scope on the output of your
transmitter for say 2 divisions of carrier. Then modulate it with a single
tone until the voltage on the scope doubles (4 divisions). That is 100%
modulation I am sure that you would agree.

Now remove the single tone and modulate with your voice until the voice
peaks hit the same 4 divisions on the scope. You are now modulating 100%
with your voice. Your peak envelope power is exactly the same with your
voice as it was with the single tone. 4 times the carrier power.

I urge you to carefully reread what I wrote in my long post on the subject.

73
Gary  K4FMX

> -----Original Message-----
> From: amradio-bounces at mailman.qth.net [mailto:amradio-
> bounces at mailman.qth.net] On Behalf Of Geoff Edmonson
> Sent: Saturday, June 18, 2011 10:44 PM
> To: Discussion of AM Radio in the Amateur Service
> Subject: Re: [AMRadio] AM power
> 
> On 06/18/2011 09:39 PM, Gary Schafer wrote:
> > For those that wonder how PEP is found, you do so by adding voltages
> in the
> > carrier with the voltage in the applied audio. Since 100% modulation
> is the
> > doubling of the plate supply voltage which causes the plate current to
> also
> > double (2x2=4) this is where the 4 times PEP comes from.
> >
> 
> Which is true if you're modulating the carrier with a single-tone
> sinusoidal wave.
> 
> that's not what comes out of our mouths.
> 
> http://www.qsl.net/wa5bxo/asyam/aam3.html
> 
> 73 = Best Regards,
> -Geoff/W5OMR
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