[AMRadio] Series capacitor equalizing resistors

[Larry Szendrei]

The voltage would divide according to the capacitance values (assuming 0
leakage in both caps). Using the formula C=Q/V, where C is capacitance
in Farads, Q is charge in Coulombs, and V is voltage (in volts, of
course!), Q necessarily has to be the same for both caps in a series
circuit once both are charged. Therefore, Q = C1/V1 = C2/V2, and the
magic of algebra yields V1/V2 = C1/C2.

73,
-Larry/NE1S

Jim Candela wrote:

> It would be interesting to see how the voltages would imbalance if the
> capacitors were poorly matched in terms of capacitance (assume equal leakage
> currents).... Any thoughts?
> 
> Regards,
> Jim Candela
> WD5JKO